https://leetcode.cn/problems/median-of-two-sorted-arrays/description/
给定两个大小分别为 m 和 n 的正序(从小到大)数组 nums1 和 nums2. 请你找出并返回这两个正序数组的 中位数
算法的时间复杂度应该为 O(log (m+n))
示例1
输入:nums1 = [1,3], nums2 = [2]
输出:2.00000
解释:合并数组 = [1,2,3] ,中位数 2
示例2
输入:nums1 = [1,2], nums2 = [3,4]
输出:2.50000
解释:合并数组 = [1,2,3,4] ,中位数 (2 + 3) / 2 = 2.5
提示
nums1.length == mnums2.length == n0 <= m <= 10000 <= n <= 10001 <= m + n <= 2000-10^6 <= nums1[i], nums2[i] <= 10^6class Solution:
def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:
nums = nums1 + nums2
nums = sorted(nums)
length = len(nums)
if length % 2 == 0:
return (nums[int(length/2)-1] + nums[int(length/2)])/2
return nums[int(length/2)]