ericpuwang

两数相加

https://leetcode.cn/problems/add-two-numbers/description/

给你两个 非空 的链表,表示两个非负的整数.它们每位数字都是按照 逆序 的方式存储的,并且每个节点只能存储 一位 数字。

请你将两个数相加,并以相同形式返回一个表示和的链表 你可以假设除了数字 0 之外,这两个数都不会以 0 开头

示例1

输入:l1 = [2,4,3], l2 = [5,6,4]
输出:[7,0,8]
解释:342 + 465 = 807.

示例2

输入:l1 = [0], l2 = [0]
输出:[0]

示例3

输入:l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
输出:[8,9,9,9,0,0,0,1]

提示

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def addTwoNumbers(self, l1: Optional[ListNode], l2: Optional[ListNode]) -> Optional[ListNode]:
        cur = dummp = ListNode()
        carry = 0
        while l1 or l2 or carry:
            if l1:
                carry += l1.val
                l1 = l1.next
            if l2:
                carry += l2.val
                l2 = l2.next
            cur.next = ListNode(carry % 10)
            carry //= 10
            cur = cur.next
        return dummp.next